求解无向图中的割点数量
#include <bits/stdc++.h>
#define io cin.tie(0), cout.tie(0), ios::sync_with_stdio(false)
#define LL long long
#define ULL unsigned long long
#define EPS 1e-8
#define INF 0x7fffffff
#define SUB -INF - 1
using namespace std;
const int N = 109;
int low[N], num[N], dfn;
bool iscut[N];
vector<int> G[N];
void dfs(int u, int fa)
{
low[u] = num[u] = ++dfn;
int child = 0;
for (int i = 0; i < G[u].size(); i++)
{
int v = G[u][i];
if (!num[v])
{
child++;
dfs(v, u);
low[u] = min(low[v], low[u]);
if (low[v] >= num[u] && u != 1)
iscut[u] = true;
}
else if (num[v] < num[u] && v != fa)
low[u] = min(low[u], num[v]);
}
if (u == 1 && child >= 2)
iscut[1] = true;
}
int main()
{
int ans, n;
while (~scanf("%d", &n) != -1)
{
if (n == 0)
break;
memset(low, 0, sizeof(low));
memset(num, 0, sizeof(num));
dfn = 0;
for (int i = 0; i <= n; i++)
G[i].clear();
int a, b;
while (scanf("%d", &a) && a)
while (getchar() != '\n')
{
scanf("%d", &b);
G[a].push_back(b);
G[b].push_back(a);
}
memset(iscut, false, sizeof(iscut));
ans = 0;
dfs(1, 1);
for (int i = 1; i <= n; i++)
ans += iscut[i];
printf("%d\n", ans);
}
return 0;
}